Hi together,

I have found a very easy way to calculate derivatives. You simply set f'(x) = f(x + i) / i = f(x + i) * -i. If one takes only the real part from the resulting complex term, one has the derivation.

For example:

f(x) = 3x + 2

f'(x) = (3(x + i) + 2) * -i =

(3x + 3i + 2) * -i =

3 – 3xi – 2i

Real Part 3

Second example:

f(x) = 2xx2

f'(x) = 2 (x + i) . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

*-i =

4x – 2×2 * i + i

Real part 4x

Third example

f(x) = 3x-3

f'(x) = 3 (x-2 + 2xi – 1) * (x + i) * -i =

(3x-3 + 6ix-2 -3x + 3ix-2 -6x -3i) * -i =

9x-2 -3x-3 * i + 3ix -6xi + 3i-2

Real part 9x-2 – 3

Here, unfortunately, a -3 remains similar to the root function as the rest in the real part. But for linear and square equations it works quite well.

Dear greetings

Your Till